7(1[x-4]1)=28

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Solution for 7(1[x-4]1)=28 equation:


Simplifying
7(1[x + -4] * 1) = 28

Reorder the terms:
7(1[-4 + x] * 1) = 28

Reorder the terms for easier multiplication:
7(1 * 1[-4 + x]) = 28

Multiply 1 * 1
7(1[-4 + x]) = 28
7([-4 * 1 + x * 1]) = 28
7([-4 + 1x]) = 28
(-4 * 7 + 1x * 7) = 28
(-28 + 7x) = 28

Solving
-28 + 7x = 28

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '28' to each side of the equation.
-28 + 28 + 7x = 28 + 28

Combine like terms: -28 + 28 = 0
0 + 7x = 28 + 28
7x = 28 + 28

Combine like terms: 28 + 28 = 56
7x = 56

Divide each side by '7'.
x = 8

Simplifying
x = 8

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